Math, asked by nsri57331, 4 months ago

tan 30 +cot 60°
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sin30+ cost 60​

Answers

Answered by Anonymous
6

Answer:

tan30°+cot60°/sin30°+cos60°

putting value of trigonometry angles

(1/^3*1/^3)/(1/2+1/2)

(1/3)/(1)

1/3 ans..

Answered by shreekrishna35pdv8u8
0

Answer:

tan 30 +cot 60°

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sin30+ cost 60

 =  \frac{ \frac{1}{ \sqrt{3}  }   +  \frac{1}{ \sqrt{3} } }{ \frac{1}{2}  +  \frac{1}{2} }  \\  =  \frac{ \frac{1 + 1}{ \sqrt{3} } }{ \frac{1 + 1}{2} }   \\ =  \frac{2}{ \sqrt{3} }  \times  \frac{2}{2}  \\  =  \frac{2}{ \sqrt{3} }

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