Question

tan 30+ tan 60÷1- tan 30 tan 60

Answer 1

tan(A+B)=tan(A)+tan(B)/1-tan(A)tan(B)

A=30. B=60

then

tan (30+60)

tan(90)

infinity

Answer 2

⇒(tan 30 +tan 60)/(1 - tan 30 tan 60)

=tan (30 +60)          (∵ tan (a+b) = (tan a +tan b)/(1 - tan a tan b) where a=30, b=60)

=tan 90

=1/0 = ∞ = not defined