Math, asked by velankyadsouza17, 1 month ago

Tan 30° Sec 45°- Tan60° Sec 30°​

Answers

Answered by Bidikha
1

Answer:

=Tan 30°sec45°- Tan60°sec30°

 =  \frac{1}{ \sqrt{3} }  \times  \sqrt{2}  -  \sqrt{3}  \times  \frac{2}{ \sqrt{3} }

 =  \frac{ \sqrt{2} }{ \sqrt{3} }  - 2

 =  \frac{ \sqrt{2} \times  \sqrt{3}  }{ \sqrt{3} \times  \sqrt{3}  }  - 2

 =  \frac{ \sqrt{6} }{3}  - 2

 =  \frac{ \sqrt{6} - 6 }{3}

 =  \frac{ \sqrt{6}(1 -  \sqrt{6})  }{3}

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