Question

Tan 36/cot 54 - sin 72/cos 18

Answer 1

Answer:

Given : cosec 54° + sin 72°

cosec 54° + sin 72° = cosec (90° - 36°) + sin (90° - 18°)

= sec 36° + Cos 18°

[ cosec (90 - θ) = secθ ,sin (90 - θ) = cos θ , ]

Hence, cosec 54° + sin 72° = sec 36° + Cos 18°.

(vi) SOLUTION :

Given : cot 85° + cos 75°

cot 85° + cos 75° = cot (90° - 5°) + cos (90° - 15°)

= tan 5° + sin 15°

[cot (90 - θ) = tan θ, cos (90 - θ) = sin θ ]

Hence, cot 85° + cos 75° = tan 5° + sin 15°

(vii) SOLUTION :

Given : sin 67° + cos 75°

sin 67° + cos 75° = sin (90° - 23°) + cos (90° - 15°)

= cos 23° + sin 15°

[sin (90 - θ) = cos θ , cos (90 - θ) = sin θ]

Hence, sin 67° + cos 75° = cos 23° + sin 15°

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