Question

tan (360° + 0) + cot (90° - 0) 1+tan (180° - O) cot (270° +0) - 2 sin cos e.​

Answer 1

Answer:

साबित करें कि: (sin(180^0+theta)cos(90^0+theta)tan(270^0-theta)cot(360^0-theta))/(sin(360^0-theta)cos(360 ^0+थीटा)cos ec(-theta)"sin"(270^0+theta))=1

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