Question

(Tan^3A/1+Tan^2A) + ( Cot^3A/1+Cot^2A) = Sec A Cosec A -2Sin A Cosec A

Answer 1

Answer:

put tan^2a = x

x+1/x = 10/3 — multiply by 3x

3x^2+3 = 10x

3 x^2 - 10 x + 3 =0

x = (+10+/-Sqrt(100–4*3*3))/6

x = (10+/-8) / 6

x = 3 or 1/3

tana = sqrt(3) or sqrt(1/3)

cota = sqrt(1/3) or sqrt(3)

tana + cota = sqrt(3) + sqrt(1/3)

tana - cota = +/- (sqrt(3) - sqrt(1/3))

Answer 2

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