tan^3A - 1/ tanA -1 = sec^2A + tanA.........prove this!
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Dear friend..........
Here is the answer:-
tan^3A-1/tanA-1
=(tanA-1)(tan^2A+1+tanA)/(tanA-1)
=tan^2A+1+tanA
=sec^2A+tanA(proved)[sec^2A-tan^2A=1]
HoPe it will help you
Here is the answer:-
tan^3A-1/tanA-1
=(tanA-1)(tan^2A+1+tanA)/(tanA-1)
=tan^2A+1+tanA
=sec^2A+tanA(proved)[sec^2A-tan^2A=1]
HoPe it will help you
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