Question

tan 3A ,tan 2A, tan A is equal to​

Answer 1

Answer:

Step-by-step explanation:

tan2A can be written as tan(3A-A)

now we have tan(a-b)=tana-tanb/1+tanatanb

here a =2A & b=A

tan2A=tan(3A-A)=tan3A-tanA/1+tan3AtanA

tan2A(1+tan3Atan2A) = tan3A-tanA

tan2A + tan2Atan3AtanA = tan3A -tanA or

tan2Atan3AtanA = tan3A -tanA-tan2A

hence proved

Thank you

Hope it helps