Math, asked by saanchimisser, 10 months ago

tan ^3theta -1/tan theta -1=sec^2theta +tan theta
Prove that lhs =rhs

Answers

Answered by NeelamG
1

(tan³theta-1)/(tan theta-1)

by using formula

(a³-b³)= (a²+b²+ab)

= (tan theta-1)(tan²theta+1+tan theta)/(tan theta-1)

= tan²theta+1+tan theta

= sec²theta+tan theta

= RHS

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