Math, asked by anandmadhav030, 1 year ago

Tan^3x + cot^3x=52
Then tan^2x + cot^2x

Answers

Answered by nordine1825
12
Tan^3x + cot^3x=52 => Tan^3x + 1/Tan^3x=52 =>  Tan^6x -52 Tan^3x + 1=0
=> tan^3x= 26-sqrt(675)
=>
 tanx= sqrt[3]{26-sqrt(675)} = a
so we can calculate easily  tan^2x + cot^2x 
tan^2x + cot^2x = a^2 + (1/a)^2
Answered by dipak62
2

Answer:

14

Step-by-step explanation:

at first by using quadric solution we can calculate the value of tanA the we easily find the value of tan^2 A + cot ^2 A

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