Question

Tan(π÷4-A)=1-tanA÷1+tanB​

Answer 1

Step-by-step explanation:

tan(A+B) = (tanA +tanB) /1-tanA.tanB

tan(pi/4-A)=

={tan(pi/4)-tanA)}/1-tanpi/4.tanA

=1-tanA/1-tanA

=1

Answer 2

Hope it helps u❤❤☺.......☺☺☺☺