Question

tan(π/4+A) . tan(π/4-A)=?​

Answer 1

Answer:

$\tan( \alpha + \beta ) = \frac{tan \alpha \: + tan \beta }{1 - tan \alpha \: tan \beta }$

then

$\frac{1 + tan a}{1 - tana} \times \frac{1 - tana}{1 + tana} = 1 \: ans.$