Question

tanθ - 4/tanθ = 3

find sin²θ​

Answer 1

Answer:

16/17       [Assuming θ belongs to First Quadrant]

Step-by-step explanation:

tanθ -4/tanθ = 3

=> tan^2 θ -4 = 3 tanθ

=> tan^2 θ -3tanθ - 4 =0

Using Quadratic formula:

x=-b+sqroot(b^2 - 4ac) / 2a

=> tan θ = 4      [ assuming θ in 1st quadrant , so neglecting tan θ = -1 ]

=> sin θ= 4/sqroot(17)

=> (sin ^ 2) θ = 16/17

Hope it helps!