tan (π/ 4 +theta )= 1-tan theta /1+tan theta
Answers
Answered by
0
Answer:
tan(4π+θ)×tan(4π−θ)
1−tan4πtanθtan4π+tanθ×1+tan4πtanθtan4π−tanθ
1−tanθ1+tanθ×1+tanθ1−tanθ=1
∴tan(4π+θ)×tan(4π−θ)=1
Similar questions