Question

tan(π/4 +x) =(1-tanx)÷1+tanx​

Answer 1

Answer:

See explaination

Step-by-step explanation:

Using  Addition formulae for tan

∣∣ ∣ ∣∣¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯aatan(A±B)=tanA±tanB1∓tanAtanBaa∣∣∣−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−

here A = x and B = π4

tan[x+(π4)]=tanx+tan(π4)1−tanxtan(π4)

now tan(π4)=1

⇒tan[x+(π4)]=1+tanx1−tanx