tan(π/4+x) =1-tanx/1+tanx
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we have,,
tan(π/4+x) = (1-tanx)/(1+tanx)
(1+tanx)/(1-tanx) = (1-tanx)/(1+tanx)
=> (1+tanx)² = (1-tanx)²
=> 1+tanx = 1-tanx
=> 2tanx = 0
=> tanx = 0
=> tanx = tan0
so,, x = 0° ...ans
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