Question

tan 40° + cot 40° = 2 sec 10°​

Answer 1

Answer:

the answer is in the picture

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Answer 2

Answer:

L.H.S-

tan 40°+cot 40°

=sin40°/cos40° + cos40°/sin40°

=sin^2 40°+ cos^2 40°/cos 40°sin40°

=1/cos 40°sin40° (as sin^2 40°+ cos^2 40°= 1)

=2/2 sin40°cos40°(lob and hor is multiples by 2)

=2/sin2×40° (as 2 sin40°cos40°= sin 2×40°)

=2×cosec 80°(as 1/sin80°=cosec 80°)

=2×cosec(90°-10°)

=2sec10° (as cosec (90°-10°)=sec10°)

* L.H.S = R.H.S (PROVED)

Step-by-step explanation:

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