Question

tan (45°+a) +tan(45°-a)=k sec2a​

Answer 1

Answer:

2

Step-by-step explanation:

$\tan(45 + a) + \tan(45 - a) = \frac{k}{ \cos(2a) } \\ \\ \frac{1 + \tan(a) }{1 - \tan(a) } + \frac{1 - \tan(a) }{1 + \tan(a) } = \frac{k}{ { \cos(a) }^{2} - { \sin(a) }^{2} } \\ \\ ons \: solving \: above \: \: \: we \: get \\ \\ 2 = k \\ \\ or \: \: \: \: k = 2$