Math, asked by khanakster, 1 day ago

tan 45° + cos 45° - sin 45°​

Answers

Answered by Anonymous
4

Answer:

Lets start to solve

tan 45°  = 1

cos 45°  = 1/root2

sin 45°  = i/root2

= 1 + 1/root2 - 1/root2

= 1

Step-by-step explanation:

Have a  nice day my friend :)

Answered by rohangupta0424
0

Answer:

\mathrm{Tan \: 45$^\circ$}=1

\mathrm{Cos \: 45$^\circ$}=\dfrac{1}{\sqrt{2}}

\mathrm{Sin \: 45$^\circ$}=\dfrac{1}{\sqrt{2}}

1+\dfrac{1}{\sqrt{2} } -\dfrac{1}{\sqrt{2} }

1 \: \: (\mathrm{Solution})

\mathrm{rohangupta0424}

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