Question

tan 48.tan 16.tan 42.tan 74 =1​

Answer 1

Answer:

Rearranging...

tan48.tan42.tan16.tan74=1

=tan (90-42).tan42.tan (90-74).tan74=1

=cot42.tan42.cot74.tan74=1

=1/tan42.tan42.1/tan74.tan74=1

=tan42/tan42.tan74/tan74

=1×1=1

1=1

hence proved :tan48.tan42.tan16.tan74=1

Answer 2

Answer:

LHS

tan (90_42).tan (90_74).tan 42.tan74

by identity of cot tita=tan (90_ tita)

cot 42.cot 74.tan42.tan74

&

cot square 42 or 74 . tan square 42 or 74

1 by identity

RHS

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