Math, asked by Anonymous, 9 months ago

tan 48degree tan 23degree tan 42degree tan 67degree.

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Answers

Answered by Anonymous
2

Answer:

 \tan48 {} {}^{0}  \tan63{}^{0}  \tan23 {}^{0}  \tan42 ^{0}

tan (90-0)= cot0

 \tan48  {}^{0}  \cot48 {}^{0}   \tan63 {}^{0} \ \cot63 ^{0}

=1

Answered by Lueenu22
0

Step-by-step explanation:

Answer:

\tan48 {} {}^{0} \tan63{}^{0} \tan23 {}^{0} \tan42 ^{0}tan48

0

tan63

0

tan23

0

tan42

0

tan (90-0)= cot0

\tan48 {}^{0} \cot48 {}^{0} \tan63 {}^{0} \ \cot63 ^{0}tan48

0

cot48

0

tan63

0

cot63

0

=1

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