Question

tan^4a+ tan^2a= sec^4 a- sec^2 a​

Answer 1

Explanation: Use one of the Pythagorean identity namely, sec2A=1+tan2A LHS = sec4A−sec2A =(sec2A)2−sec2A =(1+tan2A)2−(1+tan2A) =1+2tan2A+tan4A−1−tan2A =tan4A+tan2A = RHSRead more on Sarthaks.com - https://www.sarthaks.com/4692/how-to-prove-sec-4a-sec-2a-tan-4a-tan-2a

Answer 2

Answer:

refer to the above answer