TAN 4A +TAN9A +TAN4A TAN9A TAN13A=TAN13A
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Prove that:
tan13A-tan9A tan4A=tan13Atan9Atan4A
For this equation we will use the formula:
i) tan 2a= tan(a + a) and,
ii)tan (a + b)= (tan a+ tan b)/(1-tan a tan b)
From (i), we can say
tan 13A= tan (9A+4A)
but, tan(9A+4A)=(tan 9A + tan 4A)/ (1-tan 9Atan 4A)
Therefore tan13A=(tan 9A+tan4A)/(1-tan9Atan4A)
=tan13A-tan13Atan9Atan4A=tan 9A+tan 4A
therefore,
tan13A-tan9A-tan4A=tan13Atan9Atan4A
tan13A=tan9A+tan4A+tan13Atan9Atan4A
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