Question

[(tan 50°+ sec50°/cot 40°+cosec 40°) + cos40° ×cosec50°] =?

Answer 1

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Answer : 2

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Answer 2

Answer:

Value of $\frac{(tan50+sec50)}{(cot40+cosec40)}+cos40\times cosec50</p><p>=2$

Step-by-step explanation:

Given

$\frac{(tan50+sec50)}{(cot40+cosec40)}+cos40\times cosec50$

=$\frac{tan(90-40)+sec(90-40)}{(cot40+cosec40)}+cos40\times cosec(90-40)$

= $\frac{(cot40+cosec40)}{(cot40+cosec40)}+cos40\times sec40$

=$1+cos40 \times \frac{1}{cos40}$

= $1+1$

=$2$

Therefore,

Value of $\frac{(tan50+sec50)}{(cot40+cosec40)}+cos40\times cosec50=2$

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