Math, asked by prajaktagosavi19, 9 months ago

tan 60° + sec 60° -1
tan 60° – sec 60° +1​

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Answered by Anonymous
3

Answer:-

 \:tan 60\degree + sec \: 60 \:  \degree - 1 \\  \\  \frac{1}{ \sqrt{3} }  +  \frac{2}{ \sqrt{3} } - 1 \\  \\  \frac{ \sqrt{3} + 2 \sqrt{3}  }{3}   - 1 \\  \\  \frac{3 \sqrt{3} }{3}  - 1 \\  \\  \frac{3 \sqrt{3}  - 3}{3}  \\  \\  \sqrt{3}  - 3 \\  \\ tan  \: 60\:  \degree - se \: 60 \:  \degree + 1 \\  \\  \frac{1}{ \sqrt{3} }  -  \frac{2}{ \sqrt{3} }  - 1 \\  \\  \frac{ \sqrt{3} - 2 \sqrt{3}  }{3}  - 1 \\  \\  \frac{ \sqrt{3} }{3}  - 1 \\  \\  \frac{ \sqrt{3} - 3 }{3}

Answered by Anonymous
3

Answer:

hope this is helpful to you

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