tan 7 tan23 tan60 tan83
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tan 7= cot (90-7)
= cot 83
and tan 60=root 3
now according to question
cot 83×tan 23×tan60×tan 83
=cot 83×tan83 ×tan 60×tan 23
hence tan theta ×cot theta = 1 and tan 60=root 3
therefore
cot 83 ×tan 83 =1×root 3 tan23 digree
= cot 83
and tan 60=root 3
now according to question
cot 83×tan 23×tan60×tan 83
=cot 83×tan83 ×tan 60×tan 23
hence tan theta ×cot theta = 1 and tan 60=root 3
therefore
cot 83 ×tan 83 =1×root 3 tan23 digree
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