tan 75 degress + cot 75 degress
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Answered by
0
Answer:
100.
hope you get answer.
Answered by
1
Answer:
Step-by-step explanation:
75= a +b=30+45
tan a +tan b
=tan(a+b)/1-tan a .tan b
=tan 30+tan 45/1-tan a.tan b
={(1/√3)+1}/{1-(1/√3)(1)}
=(√3+1)/(√3-1)
So,cot75°=1/tan75°
=(√3-1)/(√3+1)
Then,tan75°+cot75°={(√3+1)2+(√3-1)2}/{(√3)2-(1)2}
=(3+1+2√3+3+1-2√3)/(3-1)
=4.
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