Question

Tan 78°
____ = ?
cot 12°​

Answer 1

answer:

$x + \sqrt{1 + {x}^{2} }$

Step-by-step explanation:

$given \\ \cot(12degree) = base \div perpendicular \\ \\ b = x \\ p = 1 \\ hypotenus \: = \sqrt{1 + {x}^{2} } \\ now \: \sec(78degree) + \tan(78degree) \\ \cosec(12degree) + \cot(12degree) \\ \sqrt{1 + {x}^{2} } \div 1 + x \\ \sec(90degree - thita \: ) \\ cosec thita \\ \tan(90degree - thita) \\ \cot(thita) \\ so \: answer \: is \: x + \sqrt{1 + {x}^{2} } \\ \\ thanks \: please \: brain \: list \: me$