Question

tan(90-A)÷cosec^2A×tanA

Answer 1

We are given that: sec 2A = cosec (A – 42°)
∴We can rewrite it as: cosec (90° - 2A) = cosec (A – 42°)
On comparing both sides, we get,
90° - 2A = A – 42 °
⇒ A + 2A = 90° + 42°
⇒ 3A = 132°
⇒ A = 44°

Answer 2

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Here's your Answer...

⤵️⤵️⤵️⤵️⤵️⤵️⤵️⤵️

Since, sec 2A = cosec (A – 42°)

It can be written as: cosec (90° - 2A) = cosec (A – 42°)
On comparing both sides, we get,
90° - 2A = A – 42 °
⇒ A + 2A = 90° + 42°
⇒ 3A = 132°
⇒ A = 44°
✔✔✔✔

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