Math, asked by harman12345, 1 year ago

tan 9° -tan 27° -tan 63° + tan 81' =

Answers

Answered by rosangiri53

20

tan9+tan81)−(tan63+tan27)

Now (tanA+tanB=Sin(A+B)/CosAcosB)

=Sin90/cos81cos9−sin90/cos63cos27

=2/2cos81cos9−2/2cos63cos27

=2/cos72−2/cos36

=2(cos36−cos72/cos36cos72)

=2(2sin54sin18/sin54sin18)

=4

Hope I helped.

Answered by brunoconti

8

Answer:

Step-by-step explanation:

BRAINLIEST BRAINLIEST BRAINLIEST BRAINLIEST BRAINLIEST BRAINLIEST

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