Question

tan
(90°+0)
sec (180-O) sin (-0)
/ sin (180 + 0) cot (360-0) cose (90+0)

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Answer 1

Answer:

L.H.S.=sin(180∘+θ)cos(90∘+θ)tan(270∘−θ)cot(360∘−θ)sin(360∘−θ)cos(360∘+θ)cosec(−θ)sin(270∘+θ)

=sin(θ)(−sin(θ))cot(θ)(−cot(θ))(−sin(θ))(cos(θ)(−cosec(θ)(−cos(θ))

=sin2θcot2θsinθcosecθcos2θ

=sin2θ(cos2θsin2θ)sinθ(1sinθ)cos2θ

=cos2θcos2θ

=1=R.H.S.

Step-by-step explanation: