tan A = 1/2,tan B=2/7 Find cot (A-B)
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Answer:
cot (A-B) = 16/3
Explanation:
Given that
Tan A = 1/2
Tan B = 2/7
We know
cot Ф = 1/ Tan Ф
Therefore, cot A = 2
cot B = 7/2
By identity
Cot (α-β) = cot α cot β + 1 / cot β - cot α
Substituting the above values.
⇒cot (A-B) = cot A cot B + 1 / cot B - cot A
⇒cot (A-B) = 2(7/2) + 1 / 7/2 - 2
⇒cot (A-B) = 7 + 1 / (7 - 2(2)/2)
⇒cot (A-B) = 8/ (7-4/2)
⇒cot (A-B) = 8/(3/2)
⇒cot (A-B) = 16/3
If you find any mistake, please let me know in the comments :)
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