Question

Tan A=1/3 sinAcosC+cosAsinC find

Answer 1

tan=1/3= p/b

so, p=1 & b= 3
h= √1+9
h=√10
so,sinA=p/h = 1/√10
cosC=1/√10
cosA=3√10
sinC=3√10

sinAcosC+cosAsinC

1/√10×1/√10+3/√10×3/√10
1/10+9/10
10/10
1 ans