Tan A=1/3 sinAcosC+cosAsinC find
Answers
Answered by
2
tan=1/3= p/b
so, p=1 & b= 3
h= √1+9
h=√10
so,sinA=p/h = 1/√10
cosC=1/√10
cosA=3√10
sinC=3√10
sinAcosC+cosAsinC
1/√10×1/√10+3/√10×3/√10
1/10+9/10
10/10
1 ans
so, p=1 & b= 3
h= √1+9
h=√10
so,sinA=p/h = 1/√10
cosC=1/√10
cosA=3√10
sinC=3√10
sinAcosC+cosAsinC
1/√10×1/√10+3/√10×3/√10
1/10+9/10
10/10
1 ans
amir273:
bhai
2/x2-5/x+2=0
hm sahi h abh
2-5x+2x2/x2
2-5x+2x2=0
2x2-5x+2=0
2x2-4x-x+2
2x(x-2)-1(x-2)
(x-2)(2x-1)=0
x=2ar x=1/2
Similar questions