tan A =1/5, tan B=2/3 show that cos 2A=sin 2B
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Step-by-step explanation:
tanA=1/5 then sinA=1/√26,cosA=5√26
tanB=2/3 then sinB=2/√13,cosB=3/√13
cos2A=1-2sin^2 and sin2B=2sinBcosB
1-2(1/√26)^2 =2×2/√13×3/√13
1-(2×1/26) =2×(6/13)
1-1/13=12/13
12/13 =12/13
cos2A =sin2B
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Answer:
you have to learn identity of
cos2theta and sin2theta
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