Question

tan A=√1-COS²A/cosA​

Answer 1

Question:-

$\bf \to \: \tan(A) = \frac{ \sqrt{1 - \cos {}^{2} (A) } }{ \cos(A) }$

Solution:-

$\bf \to \: \tan(A) = \frac{ \sqrt{1 - \cos {}^{2} (A) } }{ \cos(A) }$

Use this identity

$\bf \sin {}^{2} (A) + \cos {}^{2} (A) = 1$

$\bf \: \sin {}^{2} (A) = 1 - \cos {}^{2} (A)$

$\bf \to \: \tan(A) = \frac{ \sqrt{1 - \cos {}^{2} (A) } }{ \cos(A) }$

$\bf \to \: \tan(A) = \frac{ \sqrt{ \sin {}^{2} (A) } }{ \cos(A) }$

$\bf \to \: \tan(A) = \frac{ \sin {} (A) }{ \cos(A) }$

$\boxed { { \frac{ \sin(A) }{ \cos(A) } = \tan(A) }}$

$\tan(A) = \tan(A)$

$\red{ \bf \: hence \: proved}$

Answer 2

fluid layers, and material elements sliding against each other. There are several types of friction: Dry friction is a force that opposes the relative lateral motion of two solid surfaces in contact

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