Question

tan a/1-cot a+cot a/1-tan a =1+tan+cot=sec a cosec A​

Answer 1

Answer:

The proof of the given equality is as follows :

tanA1−cotA+cotA1−tanA=sinAcosA1−cosAsinA+cosAsinA1−sinAcosA

=sin2AcosA(sinA−cosA)+cos2AsinA(cosA−sinA)

=sin3A−cos3AcosAsinA(sinA−cosA)

=sin2A+cosAsinA+cos2AcosAsinA

=1+cosAsinAcosAsinA

=1+secAcscA.

tan A/1-cot A + cot A/1-tan A = 1+sec A cosec A

HENCE PROVED.

Step-by-step explanation:

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Answer 2

Answer:

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