tan A/1-cotA +Cot A/1-tanA=1+secA.cosecA
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Heya!!!
WE know that Tan(A) = Sin( A ) / Cos(A).
And
Cot ( A ) = Cos ( A ) / Sin ( A )
a³ - b³ = ( a - b ) {( a - b )² + 3ab }
EXP:-
Sin² ( A ). Cos² ( A )
________ + _________
Cos ( A ) × Sin ( A ) - Cos ( A ) Sin ( A )
Sin ( A ) × Cos ( A ) - Sin ( A )
Sin³ ( A ) - Cos³ ( A )
_______________________
Sin ( A ) Cos ( A ) × { Sin ( A ) - Cos ( A )}
Sin ( A ) - Cos ( A ) { Sin² ( A ) - Cos² ( A )
+ 3 Sin ( A ) × Cos ( A )
________________________________________
Sin ( A ) Cos ( A ) × { Sin ( A ) - Cos ( A ) }
1 + Sin ( A ) × Cos ( A )
_______________________
Sin ( A ) × Cos ( A )
Cosec ( A ) × Sec ( A ) + 1
WE know that Tan(A) = Sin( A ) / Cos(A).
And
Cot ( A ) = Cos ( A ) / Sin ( A )
a³ - b³ = ( a - b ) {( a - b )² + 3ab }
EXP:-
Sin² ( A ). Cos² ( A )
________ + _________
Cos ( A ) × Sin ( A ) - Cos ( A ) Sin ( A )
Sin ( A ) × Cos ( A ) - Sin ( A )
Sin³ ( A ) - Cos³ ( A )
_______________________
Sin ( A ) Cos ( A ) × { Sin ( A ) - Cos ( A )}
Sin ( A ) - Cos ( A ) { Sin² ( A ) - Cos² ( A )
+ 3 Sin ( A ) × Cos ( A )
________________________________________
Sin ( A ) Cos ( A ) × { Sin ( A ) - Cos ( A ) }
1 + Sin ( A ) × Cos ( A )
_______________________
Sin ( A ) × Cos ( A )
Cosec ( A ) × Sec ( A ) + 1
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