Question

tan A/1-cotA +Cot A/1-tanA=1+secA.cosecA

Answer 1

Hope this will help u

Answer 2

Heya!!!

WE know that Tan(A) = Sin( A ) / Cos(A).

And

Cot ( A ) = Cos ( A ) / Sin ( A )

a³ - b³ = ( a - b ) {( a - b )² + 3ab }

EXP:-

Sin² ( A ). Cos² ( A )

________ + _________

Cos ( A ) × Sin ( A ) - Cos ( A ) Sin ( A )

Sin ( A ) × Cos ( A ) - Sin ( A )

Sin³ ( A ) - Cos³ ( A )

_______________________

Sin ( A ) Cos ( A ) × { Sin ( A ) - Cos ( A )}

Sin ( A ) - Cos ( A ) { Sin² ( A ) - Cos² ( A )

+ 3 Sin ( A ) × Cos ( A )

________________________________________

Sin ( A ) Cos ( A ) × { Sin ( A ) - Cos ( A ) }

1 + Sin ( A ) × Cos ( A )

_______________________

Sin ( A ) × Cos ( A )

Cosec ( A ) × Sec ( A ) + 1