tan A /1+ sec A + 1+ sec A/ tan A is equal to
Answers
Answered by
2
tan A /1+ sec A + 1+ sec A/ tan A is equal to
tan A/(1 + sec A)] + [(1 + sec A)/tan A]
= [(tan2A + (1 + sec A)2]/ (1 + sec A)tan A
= [(sec2A – 1) + (1 + sec A)2]/ (1 + sec A)tan A {using the identity sec2x – tan2x = 1}
= [(sec A + 1) (sec A – 1 + 1 + sec A)]/ (1 + sec A)tan A
= 2 sec A/ tan A
= (2/cos A)/ (sin A/cos A)
= 2/sin A
= 2 cosec A
Answered by
1
Step-by-step explanation:
hope it helps you please mark me brainlist
Attachments:

Similar questions