Question

tan A/1 + secA - tan A/1-secA
= 2 cosec A​

Answer 1

Answer:

tanA/1+secA

=(sinA/cosA)/(1+1/cosA)

=sinA/1+cosA

and similarly,

tanA/1-secA

=sinA/cosA-1

then tanA/1+secA-tanA/1-secA

=2sinA/1-cos2A

=2/sinA

=2cosecA