Question

tan A = 1 , sin b = 1/√2 find cos(a+b)​

Answer 1

Answer:

0

Step-by-step explanation:

⇒ tanA = 1     &   sinB = 1/√2

⇒ tanA = tan45°   &  sinB = sin45°

⇒ A = 45°     &    B = 45°

Therefore,

        cos(A + B) = cos(45° + 45°)

                          = cos90°

                          = 0

Required value of cos(A + B) is 0

Answer 2

Question :-

tan A = 1 , sin b = 1/√2 find cos(a+b)?

Answer :-

• cos(a+b) = 0

Step by step explanation :-

Given :-

• tan A = 1
• sin b = 1/√2

According to the trigonometry table,

We know that,

$\rm:\longmapsto{ \tan 45 \degree = 1 } \: \: \: \: \: \\ \\ \rm:\longmapsto{ \sin45 \degree = \frac{1 }{ \sqrt{2} } }$

As be written as,

$\rm:\longmapsto{ \tan A= \tan45 \degree} \\ \\ \rm:\longmapsto{ \sin b = \sin45 \degree} \: \:$

Now, it becomes

$\rm : \longmapsto{A = 45 \degree} \\ \\ \rm : \longmapsto{b = 45 \degree}$

We have to find,

$\rm : \longmapsto{ \cos(a + b)}$

On substituting the values of a and b,

$\rm : \longmapsto{ \cos(45 \degree + 45 \degree) } \\ \\\rm : \longmapsto{ \cos90 \degree} \: \: \: \: \: \: \: \: \: \: \: \: \:$

And we know that,

$\rm : \longmapsto{ \cos90 \degree = 0}$

Answer :-

$\bf : \longmapsto \red{ \cos \: 90 \degree = 0}$

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