Question

tan A-1/tan A+1 = sec A-1/Sec A+1
answer will mark as brainliest.

Answer 1

This can't be proved but it is only possible when secA=tanA
which means sinA=1 and cosA=0

Answer 2

tanA-1/tanA+1=secA-1/secA+1

(sin/cos A-1)/sin/cos A+1=secA-1/secA+1
(sin/1/sec A-1)/sin/1/sec A+1)=secA-1/secA+1
sin A-1/sinA+1=1/1
sinA-1/sinA+1=1
sinA-1=sinA+1×1
sinA-1=sinA+1
1=1
hope it is right
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