Question

tan A + (1/ tan A) = sec A cosec A

Answer 1

$solution :$

$= = = = = = = = = = = = = = = = = = = = = =$

$we \: have \: -$

$lhs$

$=> tan \: + \frac{1}{tan}$

$= > \: \frac{sin}{cos} + 1 \frac{sin }{cos}$

$(because \: tan \: = \: \: \frac{sin}{cos} \: \: \: \: \: \: \: )$

$= > \frac{sin}{cos} + \: cos + sin$

$sin ^{2} \: + cos \: ^{2} = \frac{cos}{sin}$

$= > \frac{ \: 1 \: }{ \: cos \: } \: \times \: \frac{ \: 1 \: }{ \: sin \: }$

$(because \: sin ^{2} + cos ^{2} = 1)$

$= > sec \: \: \: \: \: cosec$

$(because \: \frac{1}{cos} = \: sec \: \frac{1}{sec} = cosec)$

$= rhs$

$hence \: proved$

$= = = = = = = = = = = = = = = = = = = = = =$

$hope \: it \: helps \: u \\ pls \: mark \: me \: as \: brainliest$

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