tan A=1 what is sinA
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Answer:
- (secA+tanA)(1−sinA)]
- ⇒[(
- cosA
- 1+sinA
- )(1−sinA)]
- ⇒
- cosA
- 1−sin
- 2
- A
- =
- cosA
- cos
- 2
- A
- ⇒cosA
- Hence, the answer is cosA.
Hope this helps you☺
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