Question

tan A/2=3/2 then, 1+cosA/1-cos A=?

Answer 1

Answer:

We know that,

cosA

= 2 cos²(A/2) - 1

= 1 - 2 sin²(A/2)

Now, (1 + cosA)/(1 - cosA)

= {1 + 2 cos²(A/2)- 1}/{1 - 1 + 2 sin²(A/2)}

= cos²(A/2) / sin²(A/2)

= 1/tan²(A/2)

= 1/(3/2)²

= 1/(9/4)

= 4/9