Question

tan A = 2 then find
(sin A + cos A) (sin A - cos A)​

Answer 1

Step-by-step explanation:

this is the correct answer ..

hipe it will help u bro

Answer 2

Answer:

3/5

Step-by-step explanation:

(sin A + cos A) (sin A - cos A)​ = sin²A - cos²A

=> sin²A - cos²A = -( cos²A - sin²A)

=> -cos2A

(sin A + cos A) (sin A - cos A)​ = - cos2A ____(1)

We know that  $cos2A = \frac{1 - tan^{2}A }{1 +tan^{2}A }$

Given, tanA = 2

=> $cos2A = \frac{1 - (2)^{2}}{1 +(2)^{2}}$

=> $cos2A = \frac{1-4}{1 + 4}$

=> cos2A = -3/5

But from equation (1)

(sin A + cos A) (sin A - cos A)​ = -(-3/5)

(sin A + cos A) (sin A - cos A)​ = 3/5

Hope it helps

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