Question

Tan A 3/4 find sinA and cosA​

Answer 1

Answer:

dear is tat question tanA = 3/4 or it is tanA3/4 ????

Answer 2

Answer:

tan A 3/4 = P/B

$h = \sqrt{b {}^{2} + p {}^{2} }$

$h = \sqrt{4 {}^{2} + 3 {}^{2} }$

h= 5

sinA = P/H = 3/5

cosA= B/H=4/5