tan A =3/4, sinA=? and cos A=?
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tanA =3/4 => sinA/cosA =3/4 =>sin²A/ cos²A=9/16 =>sin²A+cos²A/cos²A =9/16 =>1/cos²A=9/16 =>cos²A=16/9 =>cosA=4/3 then,sinA =3/4×4/3=1 [as, sinA/cosA=3/4] therefore, sinA =1 and cosA =4/3
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