Question

tan a =√3, then find sin a​

Answer 1

$tan = \frac{ \sqrt{3} }{1} = \frac{p}{b}$

$p = \sqrt{3} \: \: and \: b = 1$

${h}^{2} = {p}^{2} + {b}^{2}$

${h}^{2} = { \sqrt{3} }^{2} + {1}^{2}$

${h}^{2} = 3 + 1 = 4$

$h = \sqrt{4} = 2$

$sin \: a \: = \frac{p}{h} = \frac{ \sqrt{3} }{2}$

Answer 2

Answer:

If tan is √3

Means ∅ = 60°

putting the value of ∅ in the place of Sin a

We get,

Then Sin∅ = √3

2

Alternate method:-

Tan a = √3 =P/B

H² = B² + P²

H² = (1)² + (√3)²

H² = 1 + 3

H² = 4

H = 2

Sin∅ = √3/2