tan a-√3seca+ cota= 0 , value of a is between 0 to 90, coseca+seca=?
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Answered by
2
Answer:
False
∠B=90
o
, AB=3,BC=4,AC=5
tanA=
3
4
>d. ...(AC
2
=AB
2
+BC
2
)
(ii) True
AC
2
=AB
2
+BC
2
(12x)
2
=(5x)
2
+BC
2
,
BC=
119x
(it is possible) Pythagoras theorem
(iii) False
cosA is cosine A, cscA is cosecant
(iv) False
cotA = cotangent of ∠A not product of cot and A.
(v) False
sinθ=
hypotenuse
perpendicular
sinθ>1;
3
4
>1 [∵ hypotenuse > base > perpendicular]
sinθ will always less than 1.
Answered by
3
Answer:
refer the attachment this is the answer
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