Question

Tan A = 5/12, then (sin A + cos A) sec A

Answer 1

Given
Tan A = 5/12
we know that sec A = 1/cos A
then (sin A + cos A) sec A
= sin A * sec A + cos A * sec A
= sin A/cos A +cos A/cos A
= tan A + 1
= 5/12 + 1
= 5/12 + 12/12
= (5 + 12)/12
= 17/12